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-3x^2-150x+20000=0
a = -3; b = -150; c = +20000;
Δ = b2-4ac
Δ = -1502-4·(-3)·20000
Δ = 262500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{262500}=\sqrt{2500*105}=\sqrt{2500}*\sqrt{105}=50\sqrt{105}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-50\sqrt{105}}{2*-3}=\frac{150-50\sqrt{105}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+50\sqrt{105}}{2*-3}=\frac{150+50\sqrt{105}}{-6} $
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